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Post by Old Shendemiar on Feb 11, 2004 22:28:45 GMT
$result = mysql_query("SELECT id, name FROM games"); while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
Gives
Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /home2/hpage/public_html/p/jalarvo/netau/main_elements/_ongoinggames.php on line 11
Whats it about. Version compatibility? Works fine on my homecomputer.
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Post by Old Shendemiar on Feb 11, 2004 22:37:08 GMT
Forget it. It was an error elsewhere!
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Post by sparrowhawk on Feb 11, 2004 23:03:47 GMT
Almost always the way, isn't it? Good news is that PHP5 supports proper exception handling (using try()-catch() I think). Bad news is that it's unlikely to appear on free webhosts for quite some time.
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